> res = lm(time ~ age + gender, nym.2002)
> summary(res)
...
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 241.450 6.250 38.63 < 2e-16 ***
age 1.226 0.155 7.92 6.4e-15 ***
genderMale -29.397 3.633 -8.09 1.7e-15 ***
...
The difference is estimated to be a half-hour in total time.